Heresiarch
Korax's loyal servant, he's waiting for you after you've solved the puzzle in the Seminary. He's not someone to be trifled with, so I hope you have your most powerful artifacts to fight him.
Korax himself makes a small cameo at the start, but he's not programmed.
I programmed the Heresiarch to do what he does in the game. That means, he might lift an invincibility barrier if you hit him enough, or if you hit him at all.
Careful with the fireballs and magic projectiles he summons from one of his magic cubes.
If you hurt him enough, he might start summoning Dark Bishops, similar to D'Sparil, which goes to show how much of a he actually is.
Poison gas can pass through his barrier. Although risky, you can attack him at melee range to bypass the barrier too.
Admittedly, I made this one character to satisfy my writing urges while I was in a pretty bad time. I wanted to make something easy and simple, while leaving the more complex characters for later... shame on me.
Apparently, there was a rumor involving the ending of Heretic after you kill D'Sparil. It is believed that the dude who appears at the end, the one who watches Corvus through the crystal ball, might have been an earlier version of Korax, right before the guys from Raven Software decided to use the design for the Heresiarch after changing the second Serpent Rider's design for its final version.
As far as I know, this wasn't confirmed, so take this with a grain of salt. I like to believe this was indeed the case, though. It makes me smile a bit.
... wait, now I'm starting to think that Korax's final design was originally intended to be a Chaos Serpent variant, the one that the earlier design (meaning, the Heresiarch's final one) was intended to ride. Considering how their abilities are so similar (including the summoning thing), all of this might be true, or at least it's very likely.
If there's... y'know what?, I've put this statement at the end too many times in my bots, so you know what to do.
Создано 21 июл.
Обновлено 22 июл.
Опубликован 22 июл.